Determinants and Inverse Matrices

A-Level Further Maths · Matrices

The determinant

The determinant of a square matrix is a single number with important geometric and algebraic meaning. For a 2×2 matrix:

A = [a b; c d]      det A = |A| = ad − bc

What the determinant tells you

  • The determinant is the area scale factor of the transformation the matrix represents (in 3D, the volume scale factor).
  • A negative determinant means the transformation includes a reflection (orientation reversed).
  • If det A = 0, the matrix is singular — it has no inverse, and it maps the plane onto a line (area scale factor 0).

The inverse matrix

The inverse A⁻¹ "undoes" A: A A⁻¹ = A⁻¹A = I. For a 2×2 matrix (provided det A ≠ 0):

A⁻¹ = (1/det A) [d −b; −c −a... ]

More precisely: swap the leading-diagonal elements, change the sign of the other two, then divide by the determinant:

A⁻¹ = (1/(ad−bc)) [d −b; −c a]

Solving simultaneous equations with matrices

A system like ax + by = e, cx + dy = f can be written as AX = B, where A is the coefficient matrix. The solution is:

X = A⁻¹B

This works only if det A ≠ 0 (a unique solution). If det A = 0, the equations have no unique solution (no solution, or infinitely many).

Order of an inverse product

(AB)⁻¹ = B⁻¹A⁻¹     (note the reversed order)

Worked example

Find the inverse of A = [2 1; 3 2].

  • det A = (2×2) − (1×3) = 4 − 3 = 1.
  • A⁻¹ = (1/1)[2 −1; −3 2] = [2 −1; −3 2]. (Swap 2 and 2, negate 1 and 3.) ✓

Common mistakes

  • Computing det A as ad + bc instead of ad − bc.
  • Forgetting to divide by the determinant when finding the inverse.
  • Trying to invert a singular matrix (det = 0 has no inverse).

Exam tips

  • Always find the determinant first; if it's 0, state the matrix is singular (no inverse).
  • For the 2×2 inverse: swap the diagonal, negate the off-diagonal, divide by det.
  • Solve linear systems with X = A⁻¹B.

Key facts to remember

  • det [a b; c d] = ad − bc = area scale factor; det = 0 ⇒ singular (no inverse).
  • 2×2 inverse: A⁻¹ = (1/det A)[d −b; −c a] (swap diagonal, negate off-diagonal).
  • Solve AX = B with X = A⁻¹B; (AB)⁻¹ = B⁻¹A⁻¹.
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More on Matrices

Matrix Algebra and Transformations

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