Reciprocal and Inverse Trigonometric Functions

A-Level Maths · Pure Mathematics

Reciprocal and Inverse Trigonometric Functions

A-Level Mathematics extends the basic trigonometric functions to include their reciprocals — secant, cosecant and cotangent — and their inverse functions. Understanding their definitions, graphs and properties is essential.

Definitions

The three reciprocal trigonometric functions are:

FunctionDefinitionWritten as
Secant1 / cosθsecθ
Cosecant1 / sinθcosecθ
Cotangentcosθ / sinθ = 1 / tanθcotθ

These are not the same as the inverse trig functions. secθ means "one divided by cosθ", whereas arccos (or cos⁻¹) means "the angle whose cosine is...".

Graphs of Reciprocal Functions

y = secθ: This is the reciprocal of cosθ. It has:

  • Vertical asymptotes wherever cosθ = 0 (at θ = 90°, 270°, etc.)
  • A minimum value of 1 and maximum value of -1 (no values between -1 and 1)
  • Period of 360° (or 2π radians)
  • U-shaped curves pointing up where cosθ > 0 and pointing down where cosθ < 0

y = cosecθ: This is the reciprocal of sinθ. It has:

  • Vertical asymptotes wherever sinθ = 0 (at θ = 0°, 180°, 360°, etc.)
  • Same range restriction: |cosecθ| ≥ 1
  • Period of 360°

y = cotθ: This is the reciprocal of tanθ. It has:

  • Vertical asymptotes wherever sinθ = 0
  • Period of 180° (or π radians)
  • A decreasing function within each period

Key Identities Involving Reciprocal Functions

Two derived Pythagorean identities are particularly important:

  • 1 + tan²θ = sec²θ (dividing sin²θ + cos²θ = 1 by cos²θ)
  • 1 + cot²θ = cosec²θ (dividing sin²θ + cos²θ = 1 by sin²θ)

These are used extensively in integration (see Further Integration) and in solving equations.

Worked Example: Solve 2sec²θ = 5tanθ for 0 ≤ θ < 360°.

Step 1: Replace sec²θ using the identity: 2(1 + tan²θ) = 5tanθ

Step 2: Expand: 2 + 2tan²θ = 5tanθ

Step 3: Rearrange: 2tan²θ - 5tanθ + 2 = 0

Step 4: Factorise: (2tanθ - 1)(tanθ - 2) = 0

Step 5: tanθ = 1/2 gives θ = 26.57°, 206.57°; tanθ = 2 gives θ = 63.43°, 243.43°.

Inverse Trigonometric Functions

The inverse trigonometric functions arcsin, arccos and arctan (also written sin⁻¹, cos⁻¹, tan⁻¹) reverse the original functions. Because trig functions are many-to-one, their inverses are defined on restricted domains:

FunctionDomainRange
arcsin(x)-1 ≤ x ≤ 1-π/2 ≤ y ≤ π/2
arccos(x)-1 ≤ x ≤ 10 ≤ y ≤ π
arctan(x)all real x-π/2 < y < π/2

The graphs of inverse trig functions are reflections of the restricted original functions in the line y = x.

Key properties:

  • arcsin and arctan are odd functions: arcsin(-x) = -arcsin(x)
  • arccos is neither odd nor even, but arccos(-x) = π - arccos(x)
  • arctan(x) has horizontal asymptotes at y = ±π/2

Differentiating Inverse Trig Functions

At A-Level, you should know:

  • d/dx [arcsinx] = 1/√(1 - x²)
  • d/dx [arccosx] = -1/√(1 - x²)
  • d/dx [arctanx] = 1/(1 + x²)

These results follow from implicit differentiation. For example, if y = arcsinx then x = siny, so dx/dy = cosy = √(1 - sin²y) = √(1 - x²), and dy/dx = 1/√(1 - x²).

Worked Example: Using Identities

Show that cosecθ - sinθ = cosθcotθ.

Start from the left-hand side:

cosecθ - sinθ = 1/sinθ - sinθ

= (1 - sin²θ)/sinθ

= cos²θ/sinθ (using sin²θ + cos²θ = 1)

= cosθ × (cosθ/sinθ)

= cosθcotθ = right-hand side. QED.

Exam Tips

  • When proving identities, work from one side only — do not manipulate both sides simultaneously.
  • Sketch reciprocal graphs by first sketching the original (sin, cos, tan), marking zeros (which become asymptotes) and peaks/troughs (which become the turning points of the reciprocal).
  • The identity 1 + tan²θ = sec²θ appears constantly in integration questions — recognise it instantly.
  • When solving equations with mixed reciprocal functions, convert everything to sin and cos first, then simplify.
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