Chemical Equilibria: Kc and Kp

A-Level Chemistry ยท Kinetics and Equilibria

Dynamic equilibrium

A reversible reaction in a closed system reaches dynamic equilibrium: the forward and reverse reactions occur at the same rate, so the concentrations of reactants and products stay constant (though both reactions continue).

Le Chatelier's principle

If a change is made to a system at equilibrium, the position of equilibrium shifts to oppose the change:

  • Increase concentration of a reactant โ†’ shifts to the products.
  • Increase pressure โ†’ shifts to the side with fewer gas molecules.
  • Increase temperature โ†’ shifts in the endothermic direction.
  • A catalyst speeds up both directions equally โ†’ no shift (equilibrium reached faster).

The equilibrium constant Kc

For aA + bB โ‡Œ cC + dD:

Kc = [C]^c [D]^d รท ([A]^a [B]^b)

using equilibrium concentrations (mol dmโปยณ).

  • Kc > 1 โ†’ products favoured; Kc < 1 โ†’ reactants favoured.
  • Only temperature changes Kc. Concentration, pressure and catalysts do not change Kc (the position shifts, but K is constant).

Kp โ€” for gases

For gaseous equilibria, use partial pressures instead of concentrations:

Kp = (p_C^c ร— p_D^d) รท (p_A^a ร— p_B^b)
  • Partial pressure of a gas = mole fraction ร— total pressure.
  • Mole fraction = moles of that gas รท total moles of gas.

Effect of temperature on K

  • For an exothermic forward reaction, increasing temperature decreases K (equilibrium shifts back to reactants).
  • For an endothermic forward reaction, increasing temperature increases K.

Industrial compromise (e.g. Haber process)

Conditions are chosen to balance yield, rate and cost: e.g. the exothermic Haber process would give a higher yield at low temperature, but that's too slow โ€” so a compromise temperature (~450 ยฐC) with a catalyst and high pressure is used.

Worked example

For Nโ‚‚ + 3Hโ‚‚ โ‡Œ 2NHโ‚ƒ, what happens to the position of equilibrium if pressure is increased?

  • The left has 4 gas moles, the right has 2. Increasing pressure shifts equilibrium to the side with fewer gas moles โ†’ towards ammonia (products), increasing yield. โœ“

Common mistakes

  • Saying a catalyst or pressure changes Kc/Kp โ€” only temperature does.
  • Forgetting Kc uses equilibrium concentrations (not initial ones).
  • Getting the Kc expression upside down (products on top).

Exam tips

  • Apply Le Chatelier by asking "which change is being opposed?"
  • Write Kc/Kp correctly (products over reactants, raised to their coefficients) with units.
  • Remember only temperature alters the value of K.

Key facts to remember

  • Dynamic equilibrium: forward and reverse rates equal; Le Chatelier โ€” the system opposes any change.
  • Kc = [products]/[reactants] (equilibrium concentrations); Kp uses partial pressures; only temperature changes K.
  • Increasing T shifts equilibrium in the endothermic direction; industrial conditions are a compromise of yield, rate and cost.
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