Chemical Equilibria: Kc and Kp
Dynamic equilibrium
A reversible reaction in a closed system reaches dynamic equilibrium: the forward and reverse reactions occur at the same rate, so the concentrations of reactants and products stay constant (though both reactions continue).
Le Chatelier's principle
If a change is made to a system at equilibrium, the position of equilibrium shifts to oppose the change:
- Increase concentration of a reactant → shifts to the products.
- Increase pressure → shifts to the side with fewer gas molecules.
- Increase temperature → shifts in the endothermic direction.
- A catalyst speeds up both directions equally → no shift (equilibrium reached faster).
The equilibrium constant Kc
For aA + bB ⇌ cC + dD:
Kc = [C]^c [D]^d ÷ ([A]^a [B]^b)
using equilibrium concentrations (mol dm⁻³).
- Kc > 1 → products favoured; Kc < 1 → reactants favoured.
- Only temperature changes Kc. Concentration, pressure and catalysts do not change Kc (the position shifts, but K is constant).
Kp — for gases
For gaseous equilibria, use partial pressures instead of concentrations:
Kp = (p_C^c × p_D^d) ÷ (p_A^a × p_B^b)
- Partial pressure of a gas = mole fraction × total pressure.
- Mole fraction = moles of that gas ÷ total moles of gas.
Effect of temperature on K
- For an exothermic forward reaction, increasing temperature decreases K (equilibrium shifts back to reactants).
- For an endothermic forward reaction, increasing temperature increases K.
Industrial compromise (e.g. Haber process)
Conditions are chosen to balance yield, rate and cost: e.g. the exothermic Haber process would give a higher yield at low temperature, but that's too slow — so a compromise temperature (~450 °C) with a catalyst and high pressure is used.
Worked example
For N₂ + 3H₂ ⇌ 2NH₃, what happens to the position of equilibrium if pressure is increased?
- The left has 4 gas moles, the right has 2. Increasing pressure shifts equilibrium to the side with fewer gas moles → towards ammonia (products), increasing yield. ✓
Common mistakes
- Saying a catalyst or pressure changes Kc/Kp — only temperature does.
- Forgetting Kc uses equilibrium concentrations (not initial ones).
- Getting the Kc expression upside down (products on top).
Exam tips
- Apply Le Chatelier by asking "which change is being opposed?"
- Write Kc/Kp correctly (products over reactants, raised to their coefficients) with units.
- Remember only temperature alters the value of K.
Key facts to remember
- Dynamic equilibrium: forward and reverse rates equal; Le Chatelier — the system opposes any change.
- Kc = [products]/[reactants] (equilibrium concentrations); Kp uses partial pressures; only temperature changes K.
- Increasing T shifts equilibrium in the endothermic direction; industrial conditions are a compromise of yield, rate and cost.