Quadratic Equations
Quadratic equations
A quadratic equation has the form ax² + bx + c = 0, where the highest power is x². It usually has two solutions (called roots), because a parabola can cross the x-axis twice. There are three main methods to solve them.
Method 1: Factorising
If the quadratic factorises, this is the quickest way.
1. Rearrange so one side is = 0.
2. Factorise into two brackets.
3. Set each bracket = 0 and solve.
Example: solve x² + 7x + 12 = 0.
- Factorise:
(x + 3)(x + 4) = 0. - So
x + 3 = 0→ x = −3, orx + 4 = 0→ x = −4. - Solutions: x = −3 and x = −4.
(Why? If two things multiply to give 0, at least one must be 0.)
Method 2: The quadratic formula
Works for any quadratic (especially when it won't factorise):
x = [ −b ± √(b² − 4ac) ] ÷ 2a
Substitute a, b and c carefully (watch signs), and remember the ± gives the two roots.
Example: solve x² + 4x + 1 = 0 (a=1, b=4, c=1).
x = [ −4 ± √(16 − 4) ] ÷ 2 = [ −4 ± √12 ] ÷ 2
x ≈ −0.27 or x ≈ −3.73.
Method 3: Completing the square
Rewrite x² + bx + c as (x + b/2)² − (b/2)² + c. Useful for solving and for finding the turning point of the graph. E.g. x² + 6x + 5 = (x + 3)² − 4.
The discriminant
The part b² − 4ac tells you how many real solutions there are:
- > 0 → two real solutions.
- = 0 → one (repeated) solution.
- < 0 → no real solutions.
Worked example
Solve x² − 5x + 6 = 0 by factorising.
- Two numbers multiplying to 6, adding to −5 → −2 and −3.
(x − 2)(x − 3) = 0→ x = 2 or x = 3. ✓
Common mistakes
- Forgetting there are usually two solutions.
- Sign errors when substituting into the formula (especially with negative b or c).
- Not rearranging to = 0 before factorising.
Exam tips
- Try factorising first; use the formula if it doesn't factorise nicely.
- Write the formula out and substitute clearly for method marks.
- If asked to leave an answer in surd form, don't round.
Key facts to remember
- Quadratic: ax² + bx + c = 0, usually two roots.
- Solve by factorising (set each bracket = 0), the quadratic formula x = [−b ± √(b²−4ac)]/2a, or completing the square.
- The discriminant b² − 4ac gives the number of real solutions (>0 two, =0 one, <0 none).